Newton to Celsius
Please provide values below to convert Newton [°N] to Celsius [°C], or change ↔.
Newton [°N]
Definition: The Newton scale (°N) is a temperature scale where 0°N corresponds to the freezing point of water, and 33°N corresponds to the boiling point of water.
Historyandorigin: Developed by Sir Isaac Newton in the early 18th century, this scale was intended as an alternative to the Fahrenheit and Celsius scales.
funfact: Newton’s scale was one of the earliest attempts to quantify temperature scientifically, but it never gained widespread use.
CurrentUse: The Newton scale is now obsolete and is mostly referenced in historical contexts.
Celsius [°C]
Definition: The Celsius scale is a temperature scale where the freezing point of water is 0 degrees Celsius and the boiling point is 100 degrees Celsius at standard atmospheric pressure.
Historyandorigin: It was introduced by Swedish astronomer Anders Celsius in 1742. Originally, 0°C was the boiling point and 100°C was the freezing point, but it was later reversed.
CurrentUse: It is widely used in everyday contexts and scientific measurements in most countries.
funfact: The Celsius scale is also known as the centigrade scale because it is based on a 100-degree interval between the freezing and boiling points of water.
Newton [°N] to Celsius [°C] Conversion Table
1 Newton [°N] | -63.081818182 Celsius [°C] |
2 Newton [°N] | -60.809090909 Celsius [°C] |
3 Newton [°N] | -58.536363636 Celsius [°C] |
5 Newton [°N] | -53.990909091 Celsius [°C] |
10 Newton [°N] | -42.627272727 Celsius [°C] |
50 Newton [°N] | 48.281818182 Celsius [°C] |
100 Newton [°N] | 161.91818182 Celsius [°C] |
1000 Newton [°N] | 2207.3727273 Celsius [°C] |
10000 Newton [°N] | 22661.918182 Celsius [°C] |
100000 Newton [°N] | 227207.37273 Celsius [°C] |
1000000 Newton [°N] | 2272661.9182 Celsius [°C] |
How to Convert Newton to Celsius
1 Newton [°N] = -63.081818182 Celsius [°C]
1 Celsius [°C] = 29.196 Newton [°N]
we use cross multiplication method
Newton [°N] → Celsius [°C]
1 → -63.081818182
1.5 → ?( suppose x)
=>1.5*-63.081818182=1*x
by simplifying
x=-61.945454545